x
y
-3
-3
-2
-1
-1
0
1
2
3
1
5
7
3
9
(1)
1次関数
y
= 2
x
+ 3
y=2×(
−1
)+3
=−2+3
=
1
y=2×
0
+3
=0+3
=
3
y=2×
1
+3
=2+3
=
5
y=2×
2
+3
=4+3
=
7
y=2×
3
+3
=6+3
=
9
-1
0
1
2
3